Integrand size = 21, antiderivative size = 62 \[ \int \sec (c+d x) (a+a \sin (c+d x))^{3/2} \, dx=\frac {2 \sqrt {2} a^{3/2} \text {arctanh}\left (\frac {\sqrt {a+a \sin (c+d x)}}{\sqrt {2} \sqrt {a}}\right )}{d}-\frac {2 a \sqrt {a+a \sin (c+d x)}}{d} \]
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Time = 0.05 (sec) , antiderivative size = 62, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {2746, 52, 65, 212} \[ \int \sec (c+d x) (a+a \sin (c+d x))^{3/2} \, dx=\frac {2 \sqrt {2} a^{3/2} \text {arctanh}\left (\frac {\sqrt {a \sin (c+d x)+a}}{\sqrt {2} \sqrt {a}}\right )}{d}-\frac {2 a \sqrt {a \sin (c+d x)+a}}{d} \]
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Rule 52
Rule 65
Rule 212
Rule 2746
Rubi steps \begin{align*} \text {integral}& = \frac {a \text {Subst}\left (\int \frac {\sqrt {a+x}}{a-x} \, dx,x,a \sin (c+d x)\right )}{d} \\ & = -\frac {2 a \sqrt {a+a \sin (c+d x)}}{d}+\frac {\left (2 a^2\right ) \text {Subst}\left (\int \frac {1}{(a-x) \sqrt {a+x}} \, dx,x,a \sin (c+d x)\right )}{d} \\ & = -\frac {2 a \sqrt {a+a \sin (c+d x)}}{d}+\frac {\left (4 a^2\right ) \text {Subst}\left (\int \frac {1}{2 a-x^2} \, dx,x,\sqrt {a+a \sin (c+d x)}\right )}{d} \\ & = \frac {2 \sqrt {2} a^{3/2} \text {arctanh}\left (\frac {\sqrt {a+a \sin (c+d x)}}{\sqrt {2} \sqrt {a}}\right )}{d}-\frac {2 a \sqrt {a+a \sin (c+d x)}}{d} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 62, normalized size of antiderivative = 1.00 \[ \int \sec (c+d x) (a+a \sin (c+d x))^{3/2} \, dx=\frac {2 \sqrt {2} a^{3/2} \text {arctanh}\left (\frac {\sqrt {a+a \sin (c+d x)}}{\sqrt {2} \sqrt {a}}\right )}{d}-\frac {2 a \sqrt {a+a \sin (c+d x)}}{d} \]
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Time = 0.34 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.79
method | result | size |
default | \(-\frac {2 a \left (\sqrt {a +a \sin \left (d x +c \right )}-\sqrt {a}\, \sqrt {2}\, \operatorname {arctanh}\left (\frac {\sqrt {a +a \sin \left (d x +c \right )}\, \sqrt {2}}{2 \sqrt {a}}\right )\right )}{d}\) | \(49\) |
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Time = 0.28 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.16 \[ \int \sec (c+d x) (a+a \sin (c+d x))^{3/2} \, dx=\frac {\sqrt {2} a^{\frac {3}{2}} \log \left (-\frac {a \sin \left (d x + c\right ) + 2 \, \sqrt {2} \sqrt {a \sin \left (d x + c\right ) + a} \sqrt {a} + 3 \, a}{\sin \left (d x + c\right ) - 1}\right ) - 2 \, \sqrt {a \sin \left (d x + c\right ) + a} a}{d} \]
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\[ \int \sec (c+d x) (a+a \sin (c+d x))^{3/2} \, dx=\int \left (a \left (\sin {\left (c + d x \right )} + 1\right )\right )^{\frac {3}{2}} \sec {\left (c + d x \right )}\, dx \]
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Time = 0.27 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.29 \[ \int \sec (c+d x) (a+a \sin (c+d x))^{3/2} \, dx=-\frac {\sqrt {2} a^{\frac {5}{2}} \log \left (-\frac {\sqrt {2} \sqrt {a} - \sqrt {a \sin \left (d x + c\right ) + a}}{\sqrt {2} \sqrt {a} + \sqrt {a \sin \left (d x + c\right ) + a}}\right ) + 2 \, \sqrt {a \sin \left (d x + c\right ) + a} a^{2}}{a d} \]
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Time = 0.30 (sec) , antiderivative size = 73, normalized size of antiderivative = 1.18 \[ \int \sec (c+d x) (a+a \sin (c+d x))^{3/2} \, dx=-\frac {\sqrt {2} a^{\frac {3}{2}} {\left (2 \, \cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - \log \left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right ) + \log \left (-\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1\right )\right )} \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}{d} \]
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Timed out. \[ \int \sec (c+d x) (a+a \sin (c+d x))^{3/2} \, dx=\int \frac {{\left (a+a\,\sin \left (c+d\,x\right )\right )}^{3/2}}{\cos \left (c+d\,x\right )} \,d x \]
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